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BSCI – Building Scaleable Cisco Internetworks : 642-901 Exam

Exam Number/Code: 642-901
Exam Name:BSCI – Building Scaleable Cisco Internetworks

“BSCI – Building Scaleable Cisco Internetworks”, also known as 642-901 exam, is a Cisco certification. With the complete collection of questions and answers Q&as with Expert Explanations, Pass4sure has assembled to take you through 353 Q&As to your 642-901 Exam preparation. In the 642-901 exam resources, you will cover every field and category in CCNP helping to ready you for your successful Cisco Certification.
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QUESTION 26:
EIGRP is being configured on the PassGuide network. After the initial configuration,
the EIGRP routers form relationships with its peer routers. Which three of the
following statements correctly describe these peer relationships? (Select three)
A. EIGRP will form neighbors if the routers are not adjacent
B. EIGRP will not form neighbors if the metric K-values do not match.
C. EIGRP will not form neighbors if the router AS numbers do not match.
D. EIGRP will form neighbors over primary and secondary interface addressing.
E. EIGRP will form neighbors even though hello and hold timers do not match on the
peering interfaces.
Answer: B, C, E
Explanation:
B: To become neighbors the routers metric must be comparable.
C: EIGRP neighbors must have the same AS number.
E: It is possible for two routers to become EIGRP neighbors even though the hello and
hold timers don’t match.
Incorrect Answers:
A: Neighbor discovery/recovery is the process that routers use to dynamically learn of
other routers on their directly attached networks.
D: EIGRP doesn’t build peer relationships over secondary addresses.
Reference: Cisco White Paper, Enhanced Interior Gateway Routing Protocol

http://www.cisco.com/warp/public/103/eigrp1.html

QUESTION 27:
The PassGuide network is an EIGRP network consisting of four links (Link A, Link
B, Link C, & Link D). The costs associated with each link is A=1, B=3, C=2, D=4.
According to the variables below, which link is going to be the feasible successor?
A. Link A
B. Link B
C. Link C
D. Link D
Answer: C
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Explanation:
Link A is the best link and it therefore the successor. Link C is the next best link, and it is
therefore the feasible successor.
Incorrect Answers
A: Link A is the successor, not the feasible successor.
B: Both Link A and Link C are better than Link B.
D: The feasible successor must have Advertised Destination that is less than the Feasible
Distance.
Note: Feasible distance is the best metric along a path to a destination network, including
the metric to the neighbor advertising that path. Reported distance, or advertised distance,
is the total metric along a path to a destination network as advertised by an upstream
neighbor. A feasible successor is a path whose reported distance is less than the feasible
distance.
Reference: Enhanced Interior Gateway Routing Protocol

http://www.cisco.com/warp/public/103/eigrp1.html

QUESTION 28:
Part of the routing table of router CK1 is displayed below:
S 62.99.153.0/24 [1/0] via 209.177.64.130
172.209.12.0/32 is subnetted, 1 subnets
D EX 172.209.1
[170/2590720] via 209.179.2.114, 06:47:28, Serial0/0/0.1239
62.113.17.0/24 is variably subnetted, 2 subnets, 2 masks
D EX 99.3.215.0/24
[170/27316] via 209.180.96.45, 09:52:10, FastEthernet11/0/0
[170/27316] via 209.180.96.44, 09:52:10, FastEthernet11/0/0
25.248.17.0/24
[90/1512111] via 209.179.66.25, 10:33:13, Serial0/0/0.1400001
[90/1512111] via 209.179.66.41, 10:33:13, Serial0/0/0.1402001
62.113.1.0/24 is variably subnetted, 12 subnets, 2 masks
D 62.113.1.227/32
[90/2611727] via 209.180.96.45, 10:33:13, FastEthernet1/0/0
[90/2611727] via 209.180.96.44, 10:33:13, FastEthernet1/0/0
S* 0.0.0.0/0 [1/0] via 209.180.96.14
From analyzing the above command output, what is the administrative distance of
the external EIGRP routes?
A. 24
B. 32
C. 90
D. 170
E. 27316
F. None of the above
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Answer: D
Explanation:
By default an external EIGRP route has a value of 170. By examining the exhibit we see
that this default value of the external EIGRP routes (see D-EX in exhibit) indeed is set to
170. The first value within the brackets display the AD, so with a value of [170/27316]
the AD is 170 and the metric of the route is 27316.
Incorrect Answers:
A, B: This is the subnet mask used for some of the routes in the table.
C: This is the AD of the internal EIGRP routes, which is the default
E: This is the EIGRP metric of the external EIGRP routes.
Reference: What Is Administrative Distance?

http://www.cisco.com/warp/public/105/admin_distance.html

QUESTION 29:
The PassGuide network is shown below, along with the relevant router
configurations:
CK1 # show run
interface Loopback0
ip address 10.10.10.1 255.255.255.0
!
interface Ethernet0
ip address 172.29.1.1 255.255.255.0
media-type 10BaseT
!!
router eigrp 100
redistribute connected
network 172.29.0.0
auto-summary
no eigrp log-neighgbor-changes
!
ip classless
no ip http server
CK2 # show run
interface Ethernet0
ip address 172.29.1.2 255.255.255.0
media-type 10BaseT
!
interface Ethernet1
ip address 172.19.2.2 255.255.255.0
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media-type 10BaseT
!
router eigrp 100
network 172.19.0.0
network 172.29.0.0
!
ip classless
no ip http server
CK3 # show run
interface Ethernet1/0
ip address 172.19.2.3 255.255.255.0
!
router eigrp 100
network 172.19.0.0
auto-summary
no eigrp log-neighbor-changes
!
ip classless
ip http server
With the topology found in the graphic, what will the CK1 loopback 0 be in the CK3
routing table?
A. It will show up in the routing table as D 10.0.0/8.
B. It will show up in the routing table as D EX 10.0.0.0/8.
C. It will show up in the routing table as D 10.0.0./24.
D. It will not show up in CK3 routing table because there is no network command on
CK1 .
Answer: B
Explanation:
Because router CK1 is configured with route redistribution, it will redistribute the
connected loopback network into EIGRP. Because redistributed routes will show up as
external EIGRP routes in the routing table, choice B is correct. Although the loopback
interface is using a /24 subnet mask, EIGRP summarizes at network boundaries by
default so the network will appear as the class A network of 10.0.0.0/8 in the routing
table of the other routers.
Incorrect Answers:
A: The route will be external, since it was redistributed into EIGRP.
C: It will be external because of redistribution, and it will also be summarized since that
is the default behavior of EIGRP.
D: Although it was not configured under the EIGRP network command, it would be
redistributed because it is a connected route.
QUESTION 30:
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EIGRP has been configured as the routing protocol on the PassGuide network.
Which statements are true regarding EIGRP? (Choose three)
A. By default, EIGRP performs auto-summarization across classful network boundaries.
B. EIGRP uses an area hierarchy to increase network scalability
C. To speed convergence, EIGRP attempts to maintain a successor and feasible successor
path for each destination.
D. EIGRP uses hellos to establish neighbor relationships.
E. By default, EIGRP uses the Dijkstra algorithm to determine the best path to
destination network based on bandwidth and delay.
Answer: A, C, D